\documentclass[11pt, a4paper]{article} % --- UNIVERSAL PREAMBLE BLOCK --- \usepackage[a4paper, top=2.5cm, bottom=2.5cm, left=2cm, right=2cm]{geometry} \usepackage[english, bidi=basic, provide=*]{babel} \babelprovide[import, onchar=ids fonts]{english} % --- END UNIVERSAL PREAMBLE BLOCK --- \usepackage{amsmath} \usepackage{amssymb} \usepackage{enumitem} \usepackage{titlesec} \titleformat{\section}{\large\bfseries}{\thesection}{1em}{} \setlength{\parindent}{0pt} \begin{document} \begin{center} \Large\textbf{Further Pure 1}\\ \large Chapter 4 Inequalities with Graph Sketching Practice \end{center} \vspace{0.cm} \section*{Easier: Linear and Simple Rational Functions} \begin{enumerate}[label=\textbf{\arabic*.}] \item \begin{enumerate}[label=\textbf{\alph*)}] \item On the same set of axes, sketch the graphs of $y = x$ and $y = \frac{4}{x}$. \item Find the coordinates of the points of intersection of $y = x$ and $y = \frac{4}{x}$. \item Hence write down the solution to the inequality $x \ge \frac{4}{x}$. \end{enumerate} \vspace{0.2cm} \item $f(x) = x + 2$ and $g(x) = \frac{3}{x}$, $x \neq 0$. \begin{enumerate}[label=\textbf{\alph*)}] \item Sketch $y = f(x)$ and $y = g(x)$ on the same set of axes. \item Solve $f(x) = g(x)$. \item Hence, or otherwise, solve the inequality $f(x) < g(x)$. \end{enumerate} \vspace{0.2cm} \item \begin{enumerate}[label=\textbf{\alph*)}] \item On the same set of axes, sketch the graphs of $y = \frac{2}{x}$ and $y = \frac{1}{x-2}$. \item Find the points of intersection of the two graphs. \item Write down the solution to the inequality $\frac{2}{x} > \frac{1}{x-2}$. \end{enumerate} \vspace{0.2cm} \item \begin{enumerate}[label=\textbf{\alph*)}] \item On the same set of axes, sketch the graphs of $y = 2x - 1$ and $y = \frac{2}{x-2}$. \item Find the exact coordinates of the points of intersection of $y = 2x - 1$ and $y = \frac{2}{x-2}$. \item Solve the inequality $2x - 1 \le \frac{2}{x-2}$. \end{enumerate} \vspace{0.2cm} \item $f(x) = \frac{4}{x^2}$, $x \neq 0$ and $g(x) = x + 3$. \begin{enumerate}[label=\textbf{\alph*)}] \item Sketch $y = f(x)$ and $y = g(x)$ on the same set of axes. \item Find the coordinates of the points where the graphs intersect. \item Hence write down the solution to the inequality $f(x) < g(x)$. Give your answer using set notation. \end{enumerate} \end{enumerate} \vspace{0.2cm} \section*{Moderate: Rational vs. Rational (Linear Denominators)} \begin{enumerate}[label=\textbf{\arabic*.}, resume] \item \begin{enumerate}[label=\textbf{\alph*)}] \item On the same set of axes, sketch the graphs of $y = \frac{x+1}{x-2}$ and $y = 3$. \item Find the point of intersection of $y = \frac{x+1}{x-2}$ and $y = 3$. \item Solve the inequality $\frac{x+1}{x-2} \ge 3$. \end{enumerate} \vspace{0.2cm} \item \begin{enumerate}[label=\textbf{\alph*)}] \item On the same set of axes, sketch the graphs of $y = \frac{2x}{x+1}$ and $y = x$. \item Find the points of intersection of $y = \frac{2x}{x+1}$ and $y = x$. \item Hence, or otherwise, solve the inequality $\frac{2x}{x+1} > x$. \end{enumerate} \vspace{0.3cm} \item $f(x) = \frac{2}{x-1}$, $x \neq 1$ and $g(x) = \frac{x}{x+2}$, $x \neq -2$. \begin{enumerate}[label=\textbf{\alph*)}] \item Sketch $y = f(x)$ and $y = g(x)$ on the same set of axes. \item Solve $f(x) = g(x)$, hence write down the solution to the inequality $f(x) \le g(x)$. \end{enumerate} \vspace{0.2cm} \item \begin{enumerate}[label=\textbf{\alph*)}] \item On the same set of axes, sketch the graphs of $y = \frac{x}{x+3}$ and $y = \frac{2}{x+1}$. \item Find the exact coordinates of the points of intersection. \item Solve the inequality $\frac{x}{x+3} < \frac{2}{x+1}$. Give your answer using set notation. \end{enumerate} \vspace{0.2cm} \item \begin{enumerate}[label=\textbf{\alph*)}] \item On the same set of axes, sketch the graphs of $y = \frac{2(x-2)}{x+1}$ and $y = \frac{x-2}{x-1}$. \item Find the points of intersection of $y = \frac{2(x-2)}{x+1}$ and $y = \frac{x-2}{x-1}$. \item Write down the solution to the inequality $\frac{2(x-2)}{x+1} \ge \frac{x-2}{x-1}$. \end{enumerate} \end{enumerate} \vspace{0.2cm} \section*{Harder: Squared Denominators, Complex Rational Expressions, and Challenge Problems} \begin{enumerate}[label=\textbf{\arabic*.}, resume] \item $f(x) = \frac{3}{x^2}$, $x \neq 0$ and $g(x) = \frac{4-x}{x}$, $x \neq 0$. \begin{enumerate}[label=\textbf{\alph*)}] \item Sketch $y = f(x)$ and $y = g(x)$ on the same set of axes. \item Solve $f(x) = g(x)$. \item Hence, or otherwise, solve the inequality $f(x) > g(x)$. \end{enumerate} \vspace{0.3cm} \item \begin{enumerate}[label=\textbf{\alph*)}] \item On the same set of axes, sketch the graphs of $y = \frac{4}{x^2-9}$ and $y = \frac{1}{x-3}$. \item Find the point of intersection of the two graphs. \item Solve the inequality $\frac{4}{x^2-9} \le \frac{1}{x-3}$. \end{enumerate} \vspace{0.3cm} \item \begin{enumerate}[label=\textbf{\alph*)}] \item On the same set of axes, sketch the graphs of $y = \frac{x}{4-x}$ and $y = \frac{4x}{(x-1)^2}$. \item Find the exact points of intersection of $y = \frac{x}{4-x}$ and $y = \frac{4x}{(x-1)^2}$. \item Hence, or otherwise, solve the inequality $\frac{x}{4-x} \ge \frac{4x}{(x-1)^2}$. \end{enumerate} \vspace{0.3cm} \item \begin{enumerate}[label=\textbf{\alph*)}] \item On the same set of axes, sketch the graphs of $y = x - 1$ and $y = \frac{4(1-x)}{(x+1)(x-4)}$. \item Find the points of intersection of $y = x - 1$ and $y = \frac{4(1-x)}{(x+1)(x-4)}$. \item Write down the solution to the inequality $x - 1 \le \frac{4(1-x)}{(x+1)(x-4)}$. \end{enumerate} \vspace{0.3cm} \item \begin{enumerate}[label=\textbf{\alph*)}] \item On the same set of axes, sketch the graphs of $y = \frac{x^2}{x-2}$ and $y = x + 3$. \textit{(Note: This is beyond the specification. This graph has an oblique asymptote-- these occur when the order of the numerator is greater than the order of the denominator. Divide $x^2$ by $x-2$ to find the oblique asymptote.)}. \item Find the point of intersection of the two graphs. \item Solve the inequality $\frac{x^2}{x-2} < x + 3$. Give your answer using set notation. \end{enumerate} \end{enumerate} \end{document}